D24.3 Steric Factor

The steric factor is the fraction of collisions energetic enough to react that actually results in reaction. In the cistrans isomerization example we were just discussing, not all cis molecules with energy greater than Ea will form the trans isomer. Only specific collisions, where one molecule hits a cis molecule in a way that causes one carbon to start rotating with respect to the other carbon, will push the cis molecule forward along the reaction progress.

For a more illustrative example of why some sufficiently energetic collisions do not result in a reaction proceeding forward, consider this reaction:

CO(g) + O2(g) ⟶ CO2(g) + O(g)

The reaction energy diagram is shown below. In order to proceed forward, an O2 molecule needs to collide with a CO molecule with sufficient energy to reach the transition state, where a new C=O double bond begins to form while the O=O double bond breaks and one of the C≡O π bonds also breaks.

Figure: Reaction energy diagram: CO(g) + O2(g) → CO2(g) + O(g) reaction. The activated complex or transition state (dotted lines indicate bonds being broken and formed) corresponds to the highest energy point along the reaction coordinate.

Although there are many different possible orientations a CO and an O2 molecule can have relative to one another, consider the two presented in the activity below.

Activity: Steric Factor

Consider the reaction

CO(g) + O2(g)   ⟶   CO2(g) + O(g)

With the transition state structure in mind, consider the two scenarios presented below, where the green arrows represent the speed and direction of motion for each molecule.

Illustrated are two collisions that might take place between CO and O2. In Scenario 1, O2 collides with the oxygen side of CO. In Scenario 2, O2 collides with the carbon side.

In both scenarios, (½mv2)CO + (½mv2)O2 > Ea. Which collision is more likely to produce products? Write in your notebook an explanation of your reasoning.

Write in your notebook, then left-click here for an explanation.

Scenario 1 is more likely to lead to the formation of CO2 + O product molecules.

Because a new C=O double bond needs to form as the reaction proceeds forward, the scenario where O2 collides with the carbon side of CO (scenario 1) is more likely to lead to formation of product molecules than the scenario where O2 is colliding with the oxygen side of CO.

This relatively simple example illustrates how important the orientation of the collision is in terms of reaching the transition state and forming the desired product for a given reaction.

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Chem 109 Fall 2023 Copyright © by Jia Zhou; John Moore; and Etienne Garand is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.