6 VSEPR and Polarity

Learning Objectives

| Key Concepts and Summary | Glossary |

VSEPR Theory

Valence shell electron-pair repulsion theory (VSEPR theory) enables us to predict the molecular geometry, including approximate bond angles around a central atom, of a molecule from an examination of the number of bonds and lone electron pairs in its Lewis structure. The VSEPR model assumes that electron pairs in the valence shell of a central atom will adopt an arrangement that minimizes repulsions between these electron pairs by maximizing the distance between them. The electrons in the valence shell of a central atom form either bonding pairs or nonbonding lone pairs. The electrostatic repulsion of these electrons is reduced when they assume positions as far away from each other as possible.

As a simple example of VSEPR theory, let us predict the structure of a gaseous BeF2 molecule. The Lewis structure of BeF2 (Figure 1) shows only two electron pairs around the central beryllium atom. With two bonds and no lone pairs of electrons on the central atom, the bonds are as far apart as possible, and the electrostatic repulsion between these regions of high electron density is reduced to a minimum when they are on opposite sides of the central atom. The F-Be-F bond angle is 180° (Figure 1) in the BeF2 molecule resulting in a linear geometry.

A Lewis structure is shown. A fluorine atom with three lone pairs of electrons is single bonded to a beryllium atom which is single bonded to a fluorine atom with three lone pairs of electrons. The angle of the bonds between the two fluorine atoms and the beryllium atom is labeled, “180 degrees.”
Figure 1. The BeF2 molecule adopts a linear structure in which the two bonds are as far apart as possible, on opposite sides of the Be atom.

Table 1 illustrates electron region geometries that minimize the repulsions between regions of high electron density (bonds and/or lone pairs). Two regions of electron density around a central atom in a molecule form a linear geometry; three regions form a trigonal (or triangular) planar geometry; and four regions form a tetrahedral geometry.

Table 1: The basic electron region geometries predicted by VSEPR theory maximize the space around any region of electron density (bonds or lone pairs).
Number of Electron Domains
(bonds and/or nonbonding
electron pairs)
Two Regions Three Regions Four Regions
Spatial Arrangement Two s p orbitals are shown, which looks like a peanut shaped structure. There is an arrow portraying an angle of 180 degrees between the sp orbitals. Three sp2 orbitals are shown, which are three triangular lobes forming a perfect triangle. An arrow shows the bond angle between each lobe to be equal to 120 degrees. Four sp3 orbitals are shown, which are four triangular lobes forming a tetrahedral structure. The tetrahedral structure looks much like a tripod, with three lobes pointing down like the legs of a tripod and one lobe pointing up like the camera. An arrow shows the bond angle between each lobe to be equal to 109.5 degrees.
Dash-Wedge Notation A Lewis structure of BeH2 is shown. In a linear, straight line, a hydrogen is single bonded to a beryllium atom which is single bonded to another hydrogen. A Lewis structure of BH3 is shown. Three hydrogen atoms are all single bonded to a central boron atom. The hydrogens form a triangular shape around the boron atom. A Lewis structure of CH4, or methane, is shown. Four hydrogen atoms are all single bonded to a central carbon atom to form a tetrahedral structure.
Electron Region Geometry Linear
180º angle
Trigonal Planar
120º angle
Tetrahedral
109.5º angle

Electron Region Geometry versus Molecular Geometry

It is important to note that electron region geometry around a central atom is not the same thing as its molecular geometry. The electron region geometries shown in Table 1 describe all regions where electrons are located. Bonds and lone pairs are treated equally. Molecular geometry describes the location of the atoms, not the lone pairs of electrons. The electron region geometries will be the same as the molecular geometries when there are no lone pairs of electrons around the central atom, but they will be different when there are lone pairs present on the central atom.

For example, the methane molecule, CH4, which is the major component of natural gas, has four bonding pairs of electrons around the central carbon atom; the electron region geometry is tetrahedral, as is the molecular geometry (Figure 2). On the other hand, the ammonia molecule, NH3, also has four electron pairs associated with the nitrogen atom, and thus has a tetrahedral electron region geometry. However, one of these regions is a lone pair and this lone pair influences the shape of the molecule, giving it a molecular geometry of trigonal pyramidal (Figure 3).

A Lewis structure of CH4, or methane, is shown. Four hydrogen atoms are all single bonded to a central carbon atom to form a tetrahedral structure.
Figure 2. The molecular structure of the methane molecule, CH4, is shown with a tetrahedral arrangement of the hydrogen atoms. VSEPR structures like this one are often drawn using the dash-wedge notation.
Three images are shown and labeled, “a,” “b,” and “c.” Image a shows a nitrogen atom single bonded to three hydrogen atoms. There are four oval-shaped orbs that surround each hydrogen and one facing away from the rest of the molecule. These orbs are located in a tetrahedral arrangement. Image b shows a ball-and-stick model of the nitrogen single bonded to the three hydrogen atoms. Image c is the same as image a, but there are four curved, double headed arrows that circle the molecule and are labeled, “106.8 degrees.”
Figure 3. (a) The electron region geometry for the ammonia molecule is tetrahedral with one lone pair and three single bonds. (b) The trigonal pyramidal molecular geometry is determined from the electron region geometry. (c) The actual bond angles deviate slightly from the idealized angles because the lone pair takes up a larger region of space than do the single bonds, causing the HNH angle to be slightly smaller than 109.5°.

As seen in Figure 3, small distortions from the ideal angles in Table 1 can result from differences in repulsion between various regions of electron density. VSEPR theory predicts these distortions by establishing an order of repulsions and an order of the amount of space occupied by different kinds of electron pairs. This order of repulsions determines the amount of space occupied by different regions of electrons. A lone pair of electrons occupies a larger region of space than the electrons in a triple bond; in turn, electrons in a triple bond occupy more space than those in a double bond, and so on. The order of sizes from largest to smallest is:

lone pair > triple bond > double bond > single bond

Consider formaldehyde, H2CO, which is used as a preservative for biological and anatomical specimens (seen below). This molecule has regions of high electron density that consist of two single bonds and one double bond. The basic geometry is trigonal planar with 120° bond angles, but we see that the double bond causes slightly larger angles (121°), and the angle between the single bonds is slightly smaller (118°).

A structure of formaldehyde is shown with two hydrogens, a carbon, and an oxygen. The carbon is the central atom, with two hydrogens single bonded to the carbon pointing down and to the left and right. The bond angle between the hydrogen-carbon-hydrogen is shown to be 118 degrees. The oxygen is double bonded to the carbon and pointing straight up, with two lone pairs coming off of the oxygen. The bond angle between each hydrogen-carbon-oxygen is shown to be 121 degrees.

In the ammonia molecule, the three hydrogen atoms attached to the central nitrogen are not arranged in a flat, trigonal planar molecular geometry, but rather in a three-dimensional trigonal pyramid (Figure 3) with the nitrogen atom at the apex and the three hydrogen atoms forming the base. The ideal bond angles in a trigonal pyramidal structure are based on the tetrahedral electron pair geometry. Again, there are slight deviations from the ideal because lone pairs occupy larger regions of space than do bonding electrons. The H–N–H bond angles in NH3 are slightly smaller than the 109.5° angle in a regular tetrahedron (Table 1) because the lone pair of electrons occupy more space than a single bond (Figure 3). Table 2 illustrates the ideal molecular geometry predicted for a given combination of lone pairs and bonding pairs.

Table 2: The molecular geometries are identical to the electron region geometries when there are no lone pairs present (first column). For a particular number of electron pairs (row), the molecular geometries for one or more lone pairs are determined based on modifications of the corresponding electron region geometry.
Electron Regions Electron Region Geometry Bond Angles Nonbonding
Lone Pairs
Molecular Geometry Picture
2 Linear 180º 0 Linear Orbitals of a linear structure is shown. Two triangular lobes, which look like a peanut shaped structure, point opposite from each other, with 180 degrees between the two lobes.
3 Trigonal (or Triangular) Planar ~120º 0 Trigonal Planar Orbitals of a triangular planar structure are shown. These three triangular lobes form a triangle, with 120 degrees between each of the three lobes.
1 Bent The orbitals of a bent structure are shown. Instead of three lobes forming a triangle with 120 degrees between each lobe, the top orbital is replaced with a lone pair of electrons with two orbitals point down to the left and right.
4 Tetrahedral ~109.5º 0 Tetrahedral The orbitals of a tetrahedral are shown. There is one lobe pointing straight up with three lobes pointing slightly down, much like the legs of a tripod.
1 Trigonal Pyramidal The orbitals of a trigonal pyramidal structure are shown. This is much like a tetrahedral structure, with one lobe pointing straight up and three down like the legs of a tripod. Instead, the lobe pointing up is replaced by a lone pair of electrons, forming the shape of a three-sided pyramid.
2 Bent The orbitals of a bent or angular structure are shown. Instead of a tetrahedral structure with one lobe pointing straight up and three lobes pointing down like the legs of a tripod, two of these lobs are replaced with lone pairs of electrons, leaving just two lobes about 109.5 (or less) degrees apart.

Predicting Electron Pair Geometry and Molecular Geometry

The following procedure uses VSEPR theory to determine the electron pair geometry and molecular geometry for a given molecule:

  1. Draw the Lewis Structure of the molecule or polyatomic ion.
  2. Count the number of regions of electron density (lone pairs and bonds) around the central atom. A single, double, or triple bond counts as one region of electron density.
  3. Identify the electron region geometry based on the number of regions of electron density: linear, trigonal planar, or tetrahedral (Table 2, first column).
  4. Use the number of lone pairs to determine the molecular geometry (Table 2).

Molecular Geometry for Multicenter Molecules

When a molecule or polyatomic ion only has one central atom, the molecular geometry completely describes the shape of the molecule. Larger molecules do not have a single central atom, but are connected by a chain of interior, central atoms that each possess a “local” geometry. The way these local structures are oriented with respect to each other also influences the molecular shape, but such considerations are largely beyond the scope of this introductory discussion. For our purposes, we will only focus on determining the local geometries of single atoms.

Example 1

Predicting Geometries in Multicenter Molecules
The Lewis structure for the simplest amino acid, glycine, H2NCH2CO2H, is shown here. Predict the electron region geometry and local molecular geometry for the nitrogen atom and the two carbon atoms:

A Lewis structure depicts a nitrogen atom with one lone pair of electrons that is single bonded to two hydrogen atoms and a carbon atom, which is, in turn, single bonded to two hydrogen atoms and another carbon atom. This carbon atom is double bonded to an oxygen atom with two lone pairs of electrons and single bonded to an oxygen that has two lone pairs of electrons and a single bond to a hydrogen atom.

Solution

A Lewis structure depicts a nitrogen atom with one lone pair of electrons that is single bonded to two hydrogen atoms and a carbon atom. The atoms described are drawn with bonds that indicate a three-dimensional, tetrahedral shape around the nitrogen atom. The carbon is, in turn, single bonded to two hydrogen atoms and another carbon atom, and again, a tetrahedral, three dimensional configuration is indicated by the types of bonds. This second carbon atom is double bonded to an oxygen atom and single bonded to an oxygen that has two lone pairs of electrons and a single bond to a hydrogen atom.

Consider each central atom independently. The electron region geometries:

  • nitrogen––four regions of electron density; tetrahedral
  • carbon (CH2)––four regions of electron density; tetrahedral
  • carbon (CO2)—three regions of electron density; trigonal planar

The local molecular geometry:

  • nitrogen––three bonds, one lone pair; trigonal pyramidal
  • carbon (CH2)—four bonds, no lone pairs; tetrahedral
  • carbon (CO2)—three bonds (double bond counts as one bond), no lone pairs; trigonal planar

Check Your Learning
Another amino acid is alanine, which has the Lewis structure shown here. Predict the electron region geometry and local molecular geometry of the nitrogen atom and the three carbon atoms:

A Lewis structure depicts a nitrogen atom with two lone pairs of electrons that is single bonded to two hydrogen atoms and a carbon atom, which is, in turn, single bonded to a hydrogen atom, a methyl group and another carbon atom. This carbon atom is single bonded to an oxygen atom with two lone pairs of electrons and single bonded to an oxygen that has two lone pairs of electrons and a single bond to a hydrogen atom.

Answer:

electron region geometries: nitrogen––tetrahedral; carbon (CH)—tetrahedral; carbon (CH3)—tetrahedral; carbon (CO2)—trigonal planar

local molecular geometry: nitrogen—trigonal pyramidal; carbon (CH)—tetrahedral; carbon (CH3)—tetrahedral; carbon (CO2)—trigonal planar

Molecular Polarity and Dipole Moment

As discussed previously, polar covalent bonds connect two atoms with differing electronegativities, leaving one atom with a partial positive charge (δ+) and the other atom with a partial negative charge (δ–), as the electrons are pulled toward the more electronegative atom. This separation of charge gives rise to a bond dipole moment. This bond dipole moment can be represented as a vector, a quantity having both direction and magnitude (Figure 4). Dipole vectors are shown as arrows pointing along the bond from the less electronegative atom toward the more electronegative atom. A small plus sign is drawn on the less electronegative end to indicate the partially positive end of the bond. The length of the arrow is proportional to the magnitude of the electronegativity difference between the two atoms. For this class, you should memorize these trends of electronegativity: F > O > N > Cl >> … > C > … > H > metals

Two images are shown and labeled, “a” and “b.” Image a shows a large sphere labeled, “C,” a left-facing arrow with a crossed end, and a smaller sphere labeled “H.” Image b shows a large sphere labeled, “B,” a right-facing arrow with a crossed end, and a smaller sphere labeled “F.”
Figure 4. (a) There is a small difference in electronegativity between C and H, represented as a short vector. (b) The electronegativity difference between B and F is much larger, so the vector representing the bond moment is much longer.

A whole molecule may also have a dipole moment, depending on its molecular geometry and the polarity of each of its bonds. If the molecule does have a dipole moment, the molecule is said to be a polar molecule; otherwise the molecule is said to be nonpolar. The molecular dipole moment measures the net charge separation in the whole molecule. We determine the molecular dipole moment by adding all of the bond dipole moments in three-dimensional space.

Homonuclear diatomic molecules, such as Br2 and N2, have bond and molecular dipole moments equal to zero, because the two component atoms have equal electronegativity. For heteronuclear molecules, such as CO or HF, the molecular dipole moment is equal to the bond dipole moment, which is determined by the magnitude of difference between the two electronegativity values.

When a molecule contains more than one bond, the geometry must be taken into account. If the bonds in a molecule are arranged such that their bond dipole moments cancel (vector sum equals zero), then the molecule is nonpolar. This is the situation in CO2 (Figure 5). Each of the C=O bonds are polar, but the molecule as a whole is nonpolar. From the Lewis structure and using VSEPR theory, we determine that the CO2 molecule is linear with polar C=O bonds on opposite sides of the carbon atom. The bond dipole moments cancel because they are pointed in opposite directions. In the case of the water molecule (Figure 5), the Lewis structure shows that there are two bonds to a central atom, and the electronegativity difference between oxygen and hydrogen indicates that each of these O-H bonds has a nonzero bond dipole moment. In this case, however, the molecular geometry is bent because of the lone pairs on oxygen, and the two bond dipole moments do not cancel out. Therefore, water does have a net molecular dipole moment and is therefore a polar molecule.

Two images are shown and labeled, “a” and “b.” Image a shows a carbon atom bonded to two oxygen atoms in a ball-and-stick representation. Two arrows face away from the center of the molecule in opposite directions and are drawn horizontally like the molecule. These arrows are labeled, “Bond moments,” and the image is labeled, “Overall dipole moment equals 0.” Image b shows an oxygen atom bonded to two hydrogen atoms in a downward-facing v-shaped arrangement. An upward-facing, vertical arrow is drawn below the molecule while two upward and inward facing arrows are drawn above the molecule. The upper arrows are labeled, “Bond moments,” while the image is labeled, “Overall dipole moment.”
Figure 5. The overall molecular dipole moment of a molecule depends on the individual bond dipole moments and how they are arranged. (a) Each CO bond has a bond dipole moment, but they point in opposite directions so that the net CO2 molecule is nonpolar. (b) In contrast, water is polar because the OH bond dipole moments do not cancel out.

The OCS molecule has a structure similar to CO2, but a sulfur atom has replaced one of the oxygen atoms. To determine if this molecule is polar, we first draw the molecule with the correct geometry. VSEPR theory predicts a linear molecule:

An image shows a carbon atom double bonded to a sulfur atom and an oxygen atom which are arranged in a horizontal plane. Two arrows face away from the center of the molecule in opposite directions and are drawn horizontally like the molecule. The left-facing arrow is larger than the right-facing arrow. These arrows are labeled, “Bond moments,” and a left-facing arrow below the molecule is labeled, “Overall dipole moment.”

The C-O bond is considerably polar. Although C and S have very similar electronegativity values, S is slightly more electronegative than C, and so the C-S bond is just slightly polar. Even though these bond dipole moments are pointing in opposite directions, they will not fully cancel because they have different magnitudes. Since oxygen is more electronegative than sulfur, the overall molecular dipole moment will point towards the oxygen end of the molecule.

Chloromethane, CH3Cl, is another example of a polar molecule. Although the polar C–Cl and C–H bonds are arranged in a tetrahedral geometry, the C–Cl bond has a larger bond dipole moment than the C–H bonds, and the bond dipole moments do not cancel each other out. All of the dipoles have an upward component in the orientation shown, since carbon is more electronegative than hydrogen and less electronegative than chlorine, giving an overall molecular dipole moment going from the hydrogens through the chlorine:

Note that there is a small electronegativity difference between carbon and hydrogen and a C-H bond is slightly polar; however, the difference is quite small, and C-H bonds are often categorized as nonpolar.

The highly symmetrical molecules BF3 (trigonal planar) and CH4 (tetrahedral), in which all the polar bonds are identical and symmetrical, are nonpolar. The bonds in these molecules are arranged such that their bond dipoles cancel. However, just because a molecule contains identical bonds does not mean that the dipoles will always cancel. Many molecules that have identical bonds and lone pairs on the central atoms have bond dipoles that do not cancel. Examples include H2O, H2S, and NH3. A hydrogen atom is at the positive end and a nitrogen or sulfur atom is at the negative end of the polar bonds in these molecules:

The figure had two molecules. To the left is a central sulfur atom with two lone pairs pointing up to the left and right and single bonded to two hydrogens pointing down to the left and right. There are two small arrows pointing from each hydrogen towards the sulfur. Next to the molecule is a vertical arrow pointing up that is labeled "overall dipole moment". To the right is a molecule with a nitrogen central atom with a lone pair on top of it and three single bonds to hydrogens pointing down like tripod legs. One of the bonds is dashed and one is wedged to show that one hydrogen points out of the plane and one hydrogen points back. There are small arrows pointing from the hydrogens towards the nitrogen. Next to the molecule is a larger arrow pointing straight up labeled "overall dipole moment".

In summary, to be polar, a molecule must:

  1. Contain at least one polar covalent bond.
  2. Have a molecular geometry such that the sum of the vectors of each bond dipole moment does not equal zero.

Assignment of Hybrid Orbitals to Central Atoms

The hybridization of an atom is determined based on the number of regions of electron density that surround it. The geometrical arrangements characteristic of the various sets of hybrid orbitals are shown in Figure 25. These arrangements are identical to those of the electron region geometries predicted by VSEPR theory. VSEPR theory predicts the shapes of molecules, and hybrid orbital theory provides an explanation for how those shapes are formed. To find the hybridization of a central atom, we can use the following guidelines:

  1. Determine the Lewis structure of the molecule.
  2. Determine the number of regions of electron density around an atom using VSEPR theory, in which single bonds, multiple bonds, radicals, and lone pairs each count as one region.
  3. Assign the set of hybridized orbitals from Figure 25 that corresponds to this geometry.
A table is shown that is composed of five columns and four rows. The header row contains the phrases, “Regions of electron density,” “Arrangement,” (which has two columns below it), and “Hybridization,” (which has two columns below it). The first column contains the numbers “2,” “3,” and “4." The second column contains images of a line, a triangle, and a three sided pyramid. The third column contains the terms, “Linear,” “Trigonal planar,” and “Tetrahedral.” The fourth column contains the terms “s p,” “s p superscript 2,” and “s p superscript 3.” The last column contains drawings of the molecules beginning with a peanut-shaped structure marked with an angle of “180 degrees.” The second structure is made up of three equal-sized, rounded structures connected at one point with an angle of “120 degrees,” while the third structure is a three-dimensional arrangement of four equal-sized, rounded structures labeled as “109.5 degrees.”
Figure 25. The shapes of hybridized orbital sets are consistent with the electron region geometries. For example, an atom surrounded by three regions of electron density is sp2 hybridized, and the three sp2 orbitals are arranged in a trigonal planar fashion.

It is important to remember that hybridization was devised to rationalize experimentally observed molecular geometries. The model works well for molecules containing small central atoms, in which the valence electron pairs are close together in space. However, for larger central atoms, the valence-shell electron pairs are farther from the nucleus and there are fewer repulsions. Their compounds exhibit structures that are often not consistent with VSEPR theory and hybridized orbitals are not necessary to explain the observed data. For example, we have discussed the H–O–H bond angle in H2O (in red below), 104.5°, which is more consistent with sp3 hybrid orbitals (109.5°) on the central atom than with 2p orbitals (90°). Sulfur is in the same group as oxygen, and H2S (in yellow) has a similar Lewis structure. However, it has a much smaller bond angle (92.1°), which indicates much less hybridization on sulfur than oxygen. Continuing down the group, tellurium (in brown) is even larger than sulfur, and for H2Te, the observed bond angle (90°) is consistent with overlap of the 5p orbitals, without invoking hybridization. We invoke hybridization where it is necessary to explain the observed structures.

Three Lewis structures are shown. The left structure shows an oxygen atom with two lone pairs of electrons single bonded to two hydrogen atoms. The middle structure is made up of a sulfur atom with two lone pairs of electrons single bonded to two hydrogen atoms. The right structure is made up of a tellurium atom with two lone pairs of electrons single bonded to two hydrogen atoms. From left to right, the bond angles of each molecule decrease.

Key Concepts and Summary

In this section, we review many of the topics you are expected to be familiar with that are the foundation of organic chemistry. The first review topic is VSEPR Theory of two, three, and four electron regions. These electron region and molecular geometries enable us to predict molecular shape and bond angles. Using these molecular shapes, we can take a closer look at the electronegative of the atoms within a molecule to predict if a molecule is polar. A molecule’s polarity determines many of its physical properties, like melting point.

Glossary

bond dipole moment
the separation of charge that results when two atoms with differing electronegativites are bonded together, leaving a δ+ charge on the less electronegative atom and a δ- charge on the more electronegative atom

electron region geometry
geometry based on all regions where electrons are located (bonds and lone electron pairs)

hybridization
a widely accepted model that uses quantum mechanics to mathematically combine valence orbitals and create new hybrid orbitals. This model explains the observed bond angles in water, and many other molecules

hybrid orbitals
the new orbitals created after hybridization

molecular (overall) dipole moment
the net charge separation in a molecule

molecular geometry
geometry only based o the location of atoms, not lone electron pairs

nonpolar molecule
a molecule without a dipole moment

polarizability
the measure of how easy or difficult it is for another electrostatic charge (a nearby ion or molecule) to distort a molecule’s electron cloud

polar molecule
a molecule with a dipole moment

valence shell electron-pair repulsion theory (VSEPR theory)
a theory to predict the molecular geometry, including approximate bond angles around a central atom, of a molecule from an examination of the number of bonds and lone electron pairs in its Lewis structure

vector
a quantity having both direction and magnitude

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