D31.5 Kinetics and Equilibrium

Let’s use the reaction

cis-1,2-difluoroethene ⇄ trans-1,2-difluoroethene

again to see how a reaction’s kinetics relates to its equilibrium.

When we first considered the equilibrium of the cistrans isomerization reaction, we noted that the reaction has a ΔrG° = +3.88 kJ/mol at 615 K. Because the forward and reverse reaction has the same transition state, this ΔrG° value tells us that Ea, reverse = Ea, forward – 3880 J/mol.

For this reaction, because Ea, forward is greater than Ea, reversekforward would be smaller than kreverse. Using the arrhenius equation, we find that kforward = ½kreverse.

 \begin{array}{rcl} \dfrac{k_{\text{forward}}}{k_{\text{reverse}}} &=& \dfrac{\text{A}e^{-E_{\text{a, forward}}/RT}}{\text{A}e^{-E_{\text{a, reverse}}/RT}} = e^{(-E_{\text{a, forward}}-(-E_{\text{a, reverse}}))/RT} \\[1.5em] &=& e^{-3880\;\text{J/mol}/((8.314\;\text{J/mol·K})(615\;\text{K}))} = 0.5 \end{array}

At the beginning of this reaction, there is only cis-1,2-difluoroethene. As soon as the forward reaction produces some trans-1,2-difluoroethene, the reverse reaction begins to occur. The rate of the forward reaction is


and the rate of the reverse reaction is

ratereverse = kreverse[trans-1,2-difluoroethene]

As the reaction proceeds, the rate of the forward reaction decreases as [cis-1,2-difluoroethene] decreases, and the rate of the reverse reaction increases as [trans-1,2-difluoroethene] increases. Equilibrium is reached when rateforward = ratereverse, resulting in the concentrations of both species remaining constant over time. But equilibrium is dynamic: each individual molecule is still constantly transforming back and forth between cis and trans forms.

The kinetic energy distribution of cis molecules is exactly the same as that of trans molecules because both isomers are at 615 K. However, because Ea, forward > Ea, reverse, the fraction of cis molecules with KE > Ea is smaller than the fraction of trans molecules with KE > Ea. This means that when a molecule is in the cis form, it is less likely for it to have enough energy to reach the transition state compared to when it is in the trans form. Therefore, on average, each molecule spends ⅔ time in the cis form and ⅓ time in the trans form, giving us K° = 0.5.

K° = erG°/RT = e-(3880 J/mol)/((8.314 J/mol·K)(615 K)) = 0.5

The K° = kforward/kreverse relationship can be derived from the fact that at equilibrium rateforward = ratereverse:

kforward[cis-1,2-difluoroethene] = kreverse[trans-1,2-difluoroethene]

 \dfrac{k_{\text{forward}}}{k_{\text{reverse}}} = \dfrac{[trans\text{-1,2-difluoroethene}]}{[cis\text{-1,2-difluoroethene}]} = K^\circ

Many reactions have greater ΔrG° than the cistrans isomerization reaction, and typically greater negative ΔrG° because the forward reaction is desired. In such a case, kreverse << kforward, and you can stop the reaction before any significant reverse reaction has occurred. Equilibrium would not have been established, and that is OK: a reaction is more useful if you can maximize the quantity of desired products as quickly as possible, and reverse reaction runs counter to that end goal.

As we explore reaction kinetics in more details in the next few days, we will focus mainly on discussing the kinetics of the forward reaction. When considering the principles of chemical kinetics, it is easier to treat forward and reverse reactions separately. But all of these principles apply equally to both.


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Chemistry 109 Fall 2021 by John Moore, Jia Zhou, and Etienne Garand is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.